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| features, caliper, togu, coaching, ellipticalls, cheapest, adipose tissue, salt, technology, compare prices, statistical, product reviews, belts, endurance, cla, body fat scales, dumb, | Solving for B we missouri naturopathic doctor find B = (1/D) * [ab/(a - b)] - [b/(a - b)]. 5 Using the estimates a = 1.10 gm/cm^3 and b = 0.90 gm/cm^3 missouri naturopathic doctor (see Katch and McArdle 1977, p. 111, or Wilmore 1976, p. 123), we come up with "Siri's equation" (Siri 1956): Percentage of body fat (i.e., 100 * B) = 495/D - 450, where D is in units of gm/cm^3. The dataset provided also gives a second estimate of body fat due to Brozek, Grande, Anderson, and Keys (1963, p. 137): missouri naturopathic doctor Percentage of body fat = 457/D - 414.2, which is considered accurate for "individuals in whom the body weight has been free from large, recent fluctuations." There does not seem to be uniform agreement in the literature as to which of these two methods is best. 6 Volume, and hence the body density D, can be accurately measured in a variety of ways. |
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| 3 In the dataset provided by Dr. A. Garth Fisher (personal communication, October 5, 1994), age, weight, height, and 10 body circumference measurements are recorded for 252 men. Each cla man's percentage of body fat was accurately estimated by an underwater weighing technique discussed below. A complete listing of the variables in the dataset appears in the Appendix. 2. Determination of the Percentage of Body Fat from Underwater Weighing 4 The percentage of body fat for an individual can be estimated from body density. As an cla approximation, assume that cla the body consists of two components -- lean tissue and fat tissue. Letting D = body density, W = body weight, A = proportion of lean tissue, B = proportion of fat tissue (so A + B = 1), a = density of lean tissue, and b = density of fat tissue, we have D = weight/volume = W/[lean tissue volume + fat tissue volume] = W/[A*W/a + B*W/b] = 1/[(A/a) + (B/b)]. |
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